I need help on a simple Geometry problem?

A food company sells its corn flakes in boxes of two different sizes: the regular box and the family value box. For the family value box, the length of the box has been increased by 20% , the height has been increased by 10% , and the width remains the same.





By what percentage does the volume of the box increase from the regular box to the value box? Round your answer to the nearest percent.

I need help on a simple Geometry problem?
ummmmm... i dunno it might be f****n 3??? lolololololololololol!!!!!!!!!!!!!!!!!!
Reply:Regular box has length = L, width = W, and height = H


Regular box has volume = LWH





Family box has length = 1.2L, width = 1.1W and height=H


Family box has volume = 1.32LWH


This is 32% bigger than the regular box





note: length increased by 20% is:


L + 20%L = L + 0.20L = 1.20L
Reply:Since





Volume = LWH


then when you change


L=%26gt; 1.2L


and


H =%26gt; 1.1H





Then V =%26gt; (1.2)(1.1)V


which is a 1.32 multiplier


or a 32% increase
Reply:regular volume = length * width * height


the family box's volume = 1.2*length * width * 1.1*height


= 1.32 * regular's volume


therefore, the box's volume increased 32%
Reply:let h be the height of regular box, L is the length of the box, and w is the width


- sense the height of the box increased by 20% u take


h x .20= x


x would be the change in height or as in the amount it has increase. so take h+ x= your new height


-do the same for L, L x .10= y, take L+y= your new length


-the width is remain the same.


-sense volume= L x w x h


so the new volume is (L+y)x(h+x)x(w)


to get the percentage increase just use the new volume - old volume. what ever the number is, use that number and divide it with the volume of the old box, that is ur percentage increase.